# Hi I need help with thisquestion. A uniform metal rod, with a mass of 3.1 kg and a length of 1.2 m,is attached to a wall by a hinge at the base. A hor

Hi I need help with thisquestion. A uniform metal rod, with a mass of 3.1 kg and a length of 1.2 m,is attached to a wall by a hinge at the base. A horizontalwire bolted to the wall 0.51 m above the base of the rod holds therod at an angle of 25 degrees above the horizontal. The wireis attached to the top of the rod. (a) Find the tension inthe wire. (b) Find the horizontal and verticalcomponents of the force exerted on the rod by the hinge. Thank you
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A uniform metal rod, with a mass = 3.1 kg and alength =1.2 m, is attached to a wall by a hinge at thebase.
A horizontal wire bolted to the wall 0.51 m above thebase of the rod holds the rod at an angle of 25 degrees above thehorizontal.
The wire is attached to the top of the rod.
(a) Find the tension in the wire.
(b) Find the horizontal and vertical components ofthe force exerted on the rod by the hinge the total torque acting on the system should bezero hence

$?=\text{(perpendicular distanceto wire)( T)}-\text{( perpendicular distanceto rod )}\left(mg\right)=0$

$T=\frac{\frac{\left[\left(\frac{1}{2}\right)\left(1.2m\right)\mathrm{cos}25\right]}{\left(0.51\right)}\left(3.1kg\right)\left(9.8\frac{m}{s}2\right)}{=}32N$
(b)the horizontal component of the force exerted on therod by the hinge = 32 N since the horizontal component of the force equalto and opposes so the horizontal wire tension = 32N the vertical components of the forceexerted on the rod by the hinge $=\left(3.1kg\right)\left(9.8m/{s}^{2}\right)=30N$