A pump is to lift 18.0 Kg of water per min through a height of 3.60m. What output rating (watts) should the pump motor have? Do we do the following? P = mgy/t = \frac{(18 x 9.8 x 3.60)}{60 sec} = 10.584 W ? Thanks!

jernplate8

jernplate8

Answered question

2020-10-23

18.0 kg of water per minute must be lifted by a pump through a height of 3.60 m. What wattage output rating ought the pump motor to have?
Do we do the following? 
P=mgyt=(18x9.8x3.60)60sec=10.584W ? 
Thanks!

Answer & Explanation

SoosteethicU

SoosteethicU

Skilled2020-10-24Added 102 answers

Yes, your procedure is the right to calculate thepower.

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