A 100.0 mL sample of spring water was treated to convert anyiron present to Fe^{2+}. Addition of 25.00mL of a 0.004951M\ K_2Cr_2O_7 solution resulted

Trent Carpenter

Trent Carpenter

Answered question

2020-11-27

A 100.0 mL sample of spring water was treated to convert anyiron present to Fe2+. Addition of 25.00mL of a 0.004951M K2Cr2O7 solution resulted in the reaction. 
6Fe2++Cr2O72+14H+?6Fe3++2Cr3++7H2O 
The excess K2Cr2O7 wasback-titrated with 6.13 mL of a 0.05753 M Fe2+ solution. Calculate the ppm of iron in the sample.

Answer & Explanation

Nola Robson

Nola Robson

Skilled2020-11-28Added 94 answers

Based on the information you gave me i found that the mass in grams to be 0.021501095
In converting this to mg you get and this is the value for 100 mL then to find it for 1000 L you do:
21.501095mg.100L=x1000L
So the final answer is 215 ppm.

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