In the figure \(\displaystyle{A}{O}={O}{B}{{\tan{{5}}}^{\circ}}\)

\(\displaystyle{A}{C}={2}{O}{B}{{\tan{{5}}}^{\circ}=}{2}\times{\left({1.9}\ {m}\right)}\times{\left({0.087}\right)}={0.332}\ {m}\)

Since height of the mirrors are 1 m each, on the left side light rays get reflected 3 points at heights, 0.166 m, 0.499 m and 0.831 m and on the right mirror also at 3 places at heights,0.0.332 m, 0.665 m and 0.997m .