We can solve this using Archimedes principle.
MSK
When iceberg floats on water, Its mass = Mass of sea water displaced.

Consider V \(\displaystyle{m}^{{3}}\) be the volume of iceberg. Its mass = Volume x density \(\displaystyle={V}\times{917}={917}\ {V}=\) Mass of sea water displaced

Volume of sea water displaced = Its mass / density = 917V/1025

This is also the volume of iceberg submerged in the sea water.

Volume of iceberg above the surface of sea water = V - (917V/1025)= 0.105V

Fraction of iceberg above the surface of sea water = 0.105V/V =0.105 = 10.5% or roughly one tenth.

Consider V \(\displaystyle{m}^{{3}}\) be the volume of iceberg. Its mass = Volume x density \(\displaystyle={V}\times{917}={917}\ {V}=\) Mass of sea water displaced

Volume of sea water displaced = Its mass / density = 917V/1025

This is also the volume of iceberg submerged in the sea water.

Volume of iceberg above the surface of sea water = V - (917V/1025)= 0.105V

Fraction of iceberg above the surface of sea water = 0.105V/V =0.105 = 10.5% or roughly one tenth.