a) What is the persons
= weight/acceleration due togravity
Key idea is the scale reading is equal to the magnitude of normal force N on the passenger from the scale.
This tells us that the scale reading , which is equal to N depends on the vertical acceleration a of the cab. Substituting mg for Fg gives us N = mg +ma = m (g+a)
For any choice of acceleration. a. if it accelerates up the weight will be more because a +ve
if it accelerates downward then weight will decrease because a is - ve then.
If moving with constant speed a =0 so the weight will remain the same as 800N
When suddenly accelates up let us say acceleration = a
Then scale reads m(g + a) = 81.83( 9.8 +a)
When it is moving with constant speed means not moving with any additional acceleration . a = 0
Scale reading = mg = 800N
Resolve the force F2 into components acting along the u and v axes and determine the magnitudes of the components.
This limit takes
Discuss the continuity of the function below at x=-3. Justify you work with limits.