The boom weighs 2600N. The boom is attached with a frictionless pivot at its lower end. It is not uniform; the distance of its center of gravity from

Question

The boom weighs 2600N. The boom is attached with a frictionless pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 35% of its length. a) Find the tension in the guy wire and the horizontal and vertical components of the force exerted on the boom at its lower end. b) Does the line of action of the force exerted on the boom a tits lower end lie along the boom?

Answer 1

Taking torques about the pivot point A
$T L \sin 60 = 5000 L \cos 60 + 2600 (0.35 L) \cos 60$
or
$T = 3.14 k N$
The vertical force exerted on the boon by the pivot
$F_{v} = 5000 N + 2600 N = 7.06 N$
the Horizontal force
$F_{b} = T = 3.14 k N$
No, $\tan (\frac{F_{v}}{F_{h}})$ is not equal to zero

The boom weighs 2600N. The boom is attached with a frictionless pivot at its lower end. It is not uniform; the distance of its center of gravity from

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