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Work u\sing the left side Use the reciptional identity: cscx=1sinx cscx−sinx=1sinx−sinx Simplify the right side into a \single expression: cscx−sinx=(1−sin2x)−sinx Use the Pythagorean identity: sin2x+cos2x=1 cscx−sinx=cos2xsinx Separate as: cscx−sinx=cosxsinx×cosx Use the quotient identity: cotx=cosxsinx csc−sinx=cotxcosx
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