A jetliner can fly 6.00 hours on a full load of fuel. Without wind it flies at a speed of 2.40 X 102m/s. The planes to make a round-trip by heading du

naivlingr 2020-12-06 Answered
A jetliner can fly 6.00 hours on a full load of fuel. Without wind it flies at a speed of 2.40 X 102m/s. The planes to make a round-trip by heading due west for a certain distance,turning around, and then heading due east for the return trip.During the entire flight, however, the place encounters a 57.8 m/s wind from the jet stream, which blows from west to east. What is the maximum distance that the plane can travel due west and just be able to return home ?
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Expert Answer

dieseisB
Answered 2020-12-07 Author has 85 answers

The jetliner can fly for 6 hrs on a load of fuel, so the whole trip would have to take 6 hours.
So that is 6 hrs×(60(60))seconds1 hr
=21600 seconds it can fly
and at 120 ms21600 s=2592 km is how far the plane can travel in the round trip. let's see a diagram:
image
you can see that the wind counteracts the velocity of the plane on the departure flight so the velocity of the plane will be (24057.8)=182.2m/s
on the way back, the wind and plane velocity will add up sothe total velocity will be (240+57.8)=297.8m/s
so we can say:
so on the way back the plane travels (297.8182.2)=115.6 m/sfaster than on the departure.
the distance both ways must be the same so:
distance there =182.2 mst1
distance back =297.8 mst2
for every
if we take the ratio of these 2 : 297.8182.2
=1.6345 how many times faster the return time isthat the departure.
t1=1.6345t2. the total time (t1+t2 must be 6 hrs or 21 600 seconds)
so substitute in the above to get:
(1.6345t2)+t2=21600 seconds.
2.6345t2=21600 s
t2=8198.899 seconds.
so t1 must be 216008198.899=13401.1 seconds. now we can plug this into our distane formula above:
distance there =182.2 ms13401.1 s=2441680 m=2.44106 m is the distance that the plance can travel

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