A 0.75-kg ball is attached to a 1.0-m rope and whirled in avertical circle. The rope will break when the tension exceeds 450 N. What is the maximum speed theball can have at the bottom of the circle without breaking the rope? A) 38 m/s B) 16 m/s C) 12 m/s D) 24 m/s E) 32 m/s

waigaK

waigaK

Answered question

2021-02-21

A 1.0-m rope is used to whirl a 0.75-kg ball in a vertical circle. When the tension is greater than 450 N, the rope will snap. How fast can the ball travel at the bottom of the circle before the rope snaps?
A) 38 m/s 
B) 16 m/s 
C) 12 m/s 
D) 24 m/s 
E) 32 m/s

Answer & Explanation

tafzijdeq

tafzijdeq

Skilled2021-02-22Added 92 answers

The tension in the rope has 2 contributions:
1- from the centripetal acceleration of the circular motion
2- from gravity
The tension is maximum when the ball is at the lowest position in its circular trajectory (i.e. when the centripetal acceleration is parallel to the force of gravity)
When the ball is in this position the tension in the ropeis:
T=Fgrav+Fcent=mg+mv2r=(0.75 kg)(9.8 ms2)+0.75 kg(r)1.0 m
T=7.35 N+0.75 kgm×v2
now when T=450N the rope will break. This happens at avelocity:
450 N=7.35 N+0.75 kgm×v2
v=450 N7.35 N0.75 kgm=24.29 ms

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