Suppose that a batch of 100 items contains 6 that are defective and 94 that are non-defective. If X is the number of defective items in a randomly drawn sample of 10 items, find (a)P{X = 0} and (b) P {X > 2}.

opatovaL

opatovaL

Answered question

2021-01-19

Suppose that a batch of 100 items contains 6 that are defective and 94 that are non-defective. If X is the number of defective items in a randomly drawn sample of 10 items, find (a)P{X = 0} and (b) P {X > 2}.

Answer & Explanation

joshyoung05M

joshyoung05M

Skilled2021-01-20Added 97 answers

The event { X=0 } is the event in which 10 non-defective are drawn one after another.
It would go down like this:
The probability of the1st item being non-defective is 94/100,because there are 94 non defective items and 100 items total.
The probability of picking the 2nd non-defective is 93/99, because there are now only 93 non-defective items left, and only a total of 99 items left (we took one out, remember?).
The probability of picking the 3rd non-defective items is 92/98,and so on until all 10 items have been picked.
Each of these are independent events, so we can just multiply them together to get the final result:
(94100)(9399(9298)(9197)(9096)(8995)(8894)(8793)(8692)(8591)=(3280891282789760640062815650955529472000)0.522

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