A wood cube 0.30 m on each side has a density of 700kg/m3 and floats levelly in water. (a) What is the distance from the top of the wood to the water surface? (b) What mass has to be placed on top of the wood so that its top isjust at the water level?
Rui Baldwin
Answered question
2020-10-28
Answer & Explanation
Laaibah Pitt
Skilled2020-10-29Added 98 answers
a) A floating object displaces its own weight of water.
Mass of water displaced = 18.9 kg
Volume of water displaced = mass / density
=18.9/1000
Volume of wood above the water surface
Distance from the top of the wood to the water surface =volume / base area
= 0.09 m
b) Upthrust = 18.9 kg
The mass which has to be placed on top of the wood = 18.9kg
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