A rifle with a weight of 30 N fires a 5.0 g bullet with a speed of 300m/s. (a) Find the recoil speed of the rifle. (b) If a700 N man holds the rilfe firmly against his shoulder, find there coil speed of the man and his rifle.

Reggie 2020-11-01 Answered

A rifle with a weight of 30 N fires a 5.0 g bullet with a speed of 300m/s. (a) Find the recoil speed of the rifle. (b) If a700 N man holds the rilfe firmly against his shoulder, find there coil speed of the man and his rifle.

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Nathanael Webber
Answered 2020-11-02 Author has 117 answers
m1u1+m2u2=m1v1+m2v2
initially both gun and bullet are at rest
m1v1+m2v2=0
v1=m2v2m1
=.53009.830=49.0 ms
700+30=730 N=7309.8 kg
v1=.5×300×9.8730=2.01369 ms
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Jeffrey Jordon
Answered 2021-10-12 Author has 2262 answers

The change in the momentum of an isolated system is zero where the initial momentum equals the final momentum. The particles interact in the system without interact with the environment. So, the momentum is conserved and we use the law of conservation of momentum as given by equation (6.7) in the form

pf=pi

The system includes the rifle and the bullet. We are given the weight of the rifle by w= 30 N. So, we can calculate its mass as next

mr=wg=30N9.8 m/s2=3.06 kg

Initially, the bullet and the rifle are at rest, so their initial velocities are zero. Hence, the initial momentum of the system is zero

pf=0

mrvr+mbvb=0

vr=mbvbmr

Now, we plug the values for mb,vb and mr into equation (2) to get vr

vr=mbvbmr

=(0.005 kg)(300 m/s)3.06 kg

=- 0.49 m/s

The velocity of the rifle is 0.49 m/s in the opposite direction of the bullet.

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