The specific heat of lead is 0.030 cal/g.C. 300 grams of leadshot at 100C is mixed with 100 grams of water at 70C in an insulated container. The final temperature of the mixture is: A) 100C b) 85.5C c)79.5C d) 74.5C e)72.5C

amanf 2020-11-22 Answered
The specific heat of lead is 0.030 cal/g.C. 300 grams of leadshot at 100C is mixed with 100 grams of water at 70C in an insulated container. The final temperature of the mixture is:
A) 100C
b) 85.5C
c)79.5C
d) 74.5C
e)72.5C
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Expert Answer

unett
Answered 2020-11-23 Author has 119 answers
Principle of calirometry or heat balance states that
Heat lossed=Heat gained
m1c1(T1T)=m2c2(TT2)
m1=300grams,c1=0.030calg.C,T1=100C
m2=100grams,c2=1,T2=70C
plug the values you will get the answer 86.81C ˜ the answer is (b)
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Jeffrey Jordon
Answered 2021-09-28 Author has 2047 answers

3000.03(100T)=1001(T70)

0.09(100T)=T70

90.09T=T70

1.09T=79

T=791.0972.47C

E)

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