A coffee merchant sells three blends of coffee. A bag of houseblend contains 300 grams of Colombian beans, 50 grams of Kenyanbeans, and 150 grams of F

Tyra

Tyra

Answered question

2021-02-01

A coffee merchant sells three blends of coffee. A bag of houseblend contains 300 grams of Colombian beans, 50 grams of Kenyanbeans, and 150 grams of French roast beans. A bag of specialblend contains 200 grams of Colombian beans, 200 grams of Kenyanbeans, and 100 grams of French roast beans. A bag of Gourmet blend contains 100 grams of Colombian beans, 350 grams of Kenyanbeans and 50 grams of French roast beans. Merchant has on hand 30kg of Colombian beans, 15 kg of Kenyan beans and 15 kg of French roast beans. One bag of the house blend produces profit of $0.50 , onebag of the Special blend produces a profit of $1.50, and one bag ofthe gourmet blend produces a profit of $2.00. How many bags of eachtype should the merchant prepare if he wants to use up all of thebeans and maximize his profit? What is the maximum profit?

Answer & Explanation

tabuordy

tabuordy

Skilled2021-02-02Added 90 answers

x=3004y7z
z=3002y3x Nowtake your solution for x and plug it into the expression you have for z to get: z=3002y3(3004y7z)
Solve that for z. Now plug that z into the expression you have forx. That will give you x=f(y) and z=g(y). Plug thoseinto the profit equation and it will now be only in terms ofy. Maximization should be easy from there.

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