A 0.145 kg baseball pitched at 39.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. If the contact time between bat and ball is 1.00\times10^{-3} s,calculate the average force between the bat and ball during contest.

Joni Kenny

Joni Kenny

Answered question

2020-11-22

A 0.145 kg baseball pitched at 39.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. If the contact time between bat and ball is 1.00×103 s,calculate the average force between the bat and ball during contest.

Answer & Explanation

hajavaF

hajavaF

Skilled2020-11-23Added 90 answers

This problem is really quite simple. All you need to do is use the Ft=mv equation.
First, you are looking for force so rewrite theequation solving for force:
F=mvt
Now v is 39.0 m/s- (-52.0 m/s) = 91 m/s.
52 is negative because the ball ends up traveling in the opposite direction after coming in contact with the ball.
Now just plug in the rest of the information and you get yours answer.
F=(0.145 kg)(91 ms)1×103 s=13195N
Jeffrey Jordon

Jeffrey Jordon

Expert2021-09-29Added 2605 answers

consider the velocity towards the pitcher as positive

m=mass of the baseball=0.145 kg

v_0 = initial velocity of the baseball = - 39 m/s

= final velocity of the baseball = 52 m/s

t = time of contact = 1.00×103 sec

= average force between bat and ball

Using impulse-change in momentum equation

Ft=m(vv0)

F(1×103)=(0.145)(52(39))

F=13195N

Don Sumner

Don Sumner

Skilled2023-05-09Added 184 answers

To calculate the average force between the bat and ball during the contact, we can use the impulse-momentum principle. The formula for impulse is given by J=Δp, where J represents impulse and Δp represents the change in momentum. The average force F can be calculated using the equation F=JΔt, where Δt represents the contact time.
Given:
Mass of the baseball, m=0.145kg
Initial velocity of the baseball, vinitial=39.0m/s
Final velocity of the baseball, vfinal=52.0m/s (negative sign indicates direction)
Contact time, Δt=1.00×103s
First, let's calculate the change in momentum, Δp. The change in momentum can be calculated as Δp=m·Δv, where Δv=vfinalvinitial.
Δv=52.0m/s39.0m/s=91.0m/s
Now, we can calculate the change in momentum:
Δp=0.145kg·(91.0m/s)=13.195kg·m/s
Next, we can calculate the average force, F, using the formula F=JΔt:
F=13.195kg·m/s1.00×103s=13.195×103N
Since the force is a vector quantity, we take the magnitude of the force, resulting in a positive value:
|F|=13.195×103N=13195N
Therefore, the average force between the bat and ball during the contact is 13195 N.
RizerMix

RizerMix

Expert2023-05-09Added 656 answers

Answer:
13195N
Explanation:
Given:
Mass of the baseball, m=0.145kg
Initial velocity of the baseball, vinitial=39.0m/s
Final velocity of the baseball, vfinal=52.0m/s (negative sign indicates direction)
Contact time, Δt=1.00×103s
To calculate the average force, we can use the impulse-momentum principle. The impulse, J, is defined as the change in momentum, Δp. The average force, F, can be calculated by dividing the impulse by the contact time:
[J=Δp=m·Δv]
[F=JΔt]
First, let's calculate the change in velocity, Δv:
[Δv=vfinalvinitial=52.0m/s39.0m/s=91.0m/s]
Next, we can calculate the change in momentum, Δp:
[Δp=m·Δv=0.145kg·(91.0m/s)=13.195kg·m/s]
Finally, we can calculate the average force, F:
[F=ΔpΔt=13.195kg·m/s1.00×103s=13.195×103N]
Since force is a vector quantity, we take the magnitude of the force, resulting in a positive value:
[|F|=13.195×103N=13195N]
Therefore, the average force between the bat and ball during the contact is 13195 N.
user_27qwe

user_27qwe

Skilled2023-05-09Added 375 answers

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
Let's denote the initial velocity of the baseball as vinitial and the final velocity of the baseball after being hit as vfinal. The initial momentum of the baseball can be calculated using the formula pinitial=m·vinitial, where m is the mass of the baseball.
The final momentum of the baseball can be calculated using the same formula, but with the final velocity: pfinal=m·vfinal.
Since the contact time between the bat and ball is given, we can calculate the change in momentum (Δp) using the formula Δp=pfinalpinitial. The average force (F) between the bat and ball during the collision can be found using Newton's second law: F=ΔpΔt, where Δt is the contact time.
Now, let's calculate the average force between the bat and ball during the collision:
First, we find the initial momentum of the baseball:
pinitial=m·vinitial=(0.145kg)·(39.0m/s)=5.655kg·m/s
Next, we find the final momentum of the baseball:
pfinal=m·vfinal=(0.145kg)·(52.0m/s)=7.540kg·m/s
Now, we calculate the change in momentum:
Δp=pfinalpinitial=(7.540kg·m/s)(5.655kg·m/s)=13.195kg·m/s
Finally, we can calculate the average force using the given contact time:
F=ΔpΔt=13.195kg·m/s1.00×103s=13,195N
Therefore, the average force between the bat and ball during the collision is 13,195 N (newtons). The negative sign indicates that the force is in the opposite direction of the motion.

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