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asked 2021-02-25

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2021-02-26
Change in potential energy=qV
\(\displaystyle{V}={4.70}\cdot{10}^{{8}}\ {V}\)
\(\displaystyle{q}={1.6}\cdot{10}^{{-{19}}}={7.53}\cdot{10}^{{-{11}}}\ {J}\)
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