Two charges are located on the x axis: q1=+3.0μC at x1=+4.0 cm, and q2=+3.0μC at x2=−4.0 cm. Two other charges are located on the y axis: q3=+3.0μC at y3=+5.0 cm, and q4=−5.0μC at y4=+7.0 cm.

Step by step solution to "Two charges are located on the x axis:..."

Maiclubk

2021-03-09

Two charges are located on the x axis:

q_{1} = + 3.0 μ C

x_{1} = + 4.0

cm, and

q_{2} = + 3.0 μ C

x_{2} = - 4.0

cm. Two other charges are located on the y axis:

q_{3} = + 3.0 μ C

y_{3} = + 5.0

cm, and

q_{4} = - 5.0 μ C

y_{4} = + 7.0

cm.

Elberte

Skilled2021-03-10Added 95 answers

q_{1}

and

q_{2}

are both positive values as given in problem are correct, the electric field due to

q_{1}

and

q_{2}

should cancel each other being in the same direction and there remains the fields due to

q_{3}

and

q_{4}

both in the same direction along y - axis downward

E_{3} + E_{4} = \frac{1}{4 π ϵ_{0}} \frac{q_{3}}{r_{1}^{2}} + \frac{1}{4 π ϵ_{0}} \frac{q_{4}}{r_{2}^{2}}

= \frac{1}{4 π ϵ_{0}} [\frac{3}{5^{2}} - \frac{5}{7^{2}}] \cdot 10^{- 6}

= 9 \times 10^{9} \times [\frac{3 \times 49 - 5 \times 25}{49 \times 25}] \cdot 10^{- 6}

161.632N/C downward along -y axis

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