a) the maximum altitude reached by the rocket
b) its total time of flight
c) its horizontal range.
Lets find the maximum altitude of the rocket
Lets not worry about the components until the rocket has done accelerating.
The angle will remain constant during acceleration.
The velocity the second the rocket stops accelerating is
m/s still acting at 53 degrees.
how far has it moved in each direction
Lets look ar drawing
So we can do some basic trig to find its height and horizontal distance
now we have the height and distance when it stops accelerating. Now its a simple projectile motion question
Going back we found it had a velocity of 190 m/s
Lets split that into x and y component
a) Max altitude just concerned with y component now our old Vf is our new Vi when it reaches its maximum height the velocity final will be zero since gravity is accelerating it down
But that was after the engines remember before the engines blew it had a height of 357.4 m
so total height =1174+357.4=1531.6 m
b) so right now we know the total time to its max height but we still need to find the time it takes to free fall to earth
so lets add up the total times
3 s till engine fall , 15.4 s till it reaches max alt and 17.6 seconds down
Total time = 36 s
c) horinzontal range
once the engines blew the x velocity was constant.
d=114.3(33) the first 3 seconds werent constant
but we must add on the original distance when engine blew
so total distance =3771.9+261.7=4033.6 m
Speed of the rocket after 3seconds =
vertical displacement =
horizontal displacement =
max Altitude = 649.8 + 348 = 997.8 m
time of flight under gravity is give by
total time of flight = 32.5 + 3 =35.5 s
horizontal range =
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1. (Enter in box 1)
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3. ( Enter in box 3) m/s
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4. ( Enter in box 4)
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Determine the coordinates of the centroid of the shaded area.