A 0.450 kg ice puck, moving east with a speed of 3.00 \frac{m}{s} has a head in collision with a 0.900 kg puck, initially at rest. Assuming a perfectly elastic collision what will be the speed and direction of each object after the collision?

Tabansi

Tabansi

Answered question

2021-02-06

A 0.450 kg ice puck, moving east with a speed of 3.00ms has a head in collision with a 0.900 kg puck, initially at rest. Assuming a perfectly elastic collision what will be the speed and direction of each object after the collision?

Answer & Explanation

curwyrm

curwyrm

Skilled2021-02-07Added 87 answers

The final speeds of the two pucks are given by:
v=[(Mm)(M+m)]
where v is the initial speed of the smaller puck
V=[2mM+m]
The smaller puck will rebound and travel in the opposite direction of its original velocity at speed:
V=[0.9000.4500.900+0.450]3.00=1.00 ms
and the larger puck will continue in the same direction as the original velocity of the small puck:
V=[20.4500.900+0.450]3.00=2.00 ms

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