You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 tall, is walking along side the building at

Suman Cole 2021-03-07 Answered

You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 tall, is walking along side the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor's head, how far from the building should the professor be when you release the egg? Assume that the egg is in free fall.Take the free fall acceleration to be 9.80 ms2

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Expert Answer

Bertha Stark
Answered 2021-03-08 Author has 96 answers
Height of building (h) = 46.0 m
Height of walling person (h1) = 1.2 ms
Initial velocity of the egg is (v0x) =0 ms
Speed of egg (v)=2gh, where g=9.8ms2
=2(9.8)(46)=30.03 ms
Let the egg drops on the persons
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Jeffrey Jordon
Answered 2021-09-24 Author has 2262 answers

S=μt+12gt2

44.2=0t+12×98×t2

t2=3s

 Professor should be at distance of 3×1.23.6 m

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Jeffrey Jordon
Answered 2021-10-05 Author has 2262 answers

Take the positive y direction to be downward. When the egg fall it has to reach the professor height so, it has to travel yy0=461.8=44.2m. While the is falling the professor moves a distance x that we are interested in.

t=xprovpro

yy0=v0t+12gt2

Substitute from the second equation into the second we get:

44.2=0+4.9×xpro2vpro2

xpro2=1.22×44.24.9=12.98

xpro=3.6m

The professor should be 3.6m away from the building

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