Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force \vec{F} The magnitude

Annette Arroyo 2020-10-18 Answered
Three identical blocks connected by ideal strings are being pulled along a horizontal frictionless surface by a horizontal force F The magnitude of the tension in the string between blocks B and C is T=3.00N. Assume that each block has mass m=0.400kg.
What is the magnitude F of the force?
What is the tension in the string between block A and block B?
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Expert Answer

Ezra Herbert
Answered 2020-10-19 Author has 99 answers
The magnitude of F of the force
T=ma
3.00N=0.400kga
thus
a=7.5 ms2
But this is the total acceleration, now for each individual block the
a=7.52=3.75 ms2
now one can find F by using
a=F3m and solving for F
F=a3m
F=4.5N
For the Tension between block A and B, all we do is
T=ma, knowing that a=3.75 ms2 for each block.
T=(0.400 kg)(3.75 ms2)=1.5N
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Jeffrey Jordon
Answered 2021-10-05 Author has 2064 answers

T2=3N

M=0.4 kg

T1=0.4a  -(1)

T2T1=0.4a -(2)

FT2=0.4a -(3)

a=3.75m/s2,TAB=1.5N

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