We don't actually need ww in this case.

Remember that the polar form of a complex number is

\(z=re^{iθ}\oslash\)

where rr is the norm of z and θ angle it makes with the xx axis.

Using a little trigonometry (form a right triangle using the negative xx axis, the arrow shown and a straight line segment between them), we know that

\(r = \sqrt{√2^{2}+1^{2}}=\sqrt{3}\)

and that

\(\tan(π−\oslash) = \frac{1}{\sqrt{2}}\)

\(π−\oslash=\arctan \frac{1}{\sqrt{2}}\)

\(\oslash=\pi−\arctan \frac{1}{\sqrt{2}}\)

Hence the polar form of z is

\(\boxed{z = \sqrt{3}e^{[\pi - \arctan(1/,\sqrt{2})]i}}\)

which is approximately

\(z=1.73e^{2.53i}\)