Q. 2# (x+1)frac{dy}{dx}=x(y^{2}+1)

Jason Farmer

Jason Farmer

Answered question

2021-02-08

Q. 2# (x+1)dydx=x(y2+1)

Answer & Explanation

unessodopunsep

unessodopunsep

Skilled2021-02-09Added 105 answers

Here the Differential equations is given by
(x+1)dydx=x(y2+1)
dyy2+1=xdxx+1
dyy2+1=xdxx+1
tan1(y)=x+11dx(x+1)+c
tan1(y)=(x+11)dx)x+1+c
tan1(y)=dxdx(x+1)+c
tan1(y)=xlnx+1+c
y=tan(xlnx+1+c),
where cc is a arbitrary constant.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Differential Equations

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?