Q. 2# (x+1)frac{dy}{dx}=x(y^{2}+1)

Jason Farmer 2021-02-08 Answered
Q. 2# (x+1)dydx=x(y2+1)
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unessodopunsep
Answered 2021-02-09 Author has 105 answers
Here the Differential equations is given by
(x+1)dydx=x(y2+1)
dyy2+1=xdxx+1
dyy2+1=xdxx+1
tan1(y)=x+11dx(x+1)+c
tan1(y)=(x+11)dx)x+1+c
tan1(y)=dxdx(x+1)+c
tan1(y)=xlnx+1+c
y=tan(xlnx+1+c),
where cc is a arbitrary constant.
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