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# part of $10,000 is invested at 11% simple interest account, the rest is at 14% simple interest account. If the annual income is$1,265, how much is invested at each rate? (solve the equations/ inequalities for x)

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Trigonometry
asked 2020-10-23
part of $10,000 is invested at 11% simple interest account, the rest is at 14% simple interest account. If the annual income is$1,265, how much is invested at each rate? (solve the equations/ inequalities for x)

## Answers (1)

2020-10-24
let x equal 11% , and y equal 14%
$$x + y = 10,000 ... .14x+14y = 1400$$
$$.11 x + 14 y = 1265$$ subtracting equations ... $$03 x = 135 ... x = 4500 ... y = 5500$$

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