Differentiate the power series for f(x)=xe^x. Use the result to find the sum of the infinite series sum_{n=0}^inftyfrac{n+1}{n!}

Tazmin Horton

Tazmin Horton

Answered question

2021-03-02

Differentiate the power series for f(x)=xex. Use the result to find the sum of the infinite series
n=0n+1n!

Answer & Explanation

sovienesY

sovienesY

Skilled2021-03-03Added 89 answers

Consider the function f(x)=xex
Differentiate the above function to get,

f(x)=ddx(xex)

=xex+ex
=n=0(n+1)xnn!
Substitute 1 for x in the above series,
1e1+e1=n=0(n+1)(1)nn!
2e=n=0(n+1)n!
n=0(n+1)n!5.4363
Thus, the sum of the infinite series is approximately 5.436.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?