Find the sum of the series. sum_{n=1}^inftyfrac{2}{(n+8)(n+6)}

Braxton Pugh 2020-11-24 Answered
Find the sum of the series.
n=12(n+8)(n+6)
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aprovard
Answered 2020-11-25 Author has 94 answers
The series is:
n=12(n+8)(n+6)
Simplify the series.
n=12(n+8)(n+6)=n=186(n+8)(n+6)
=n=1(n+8)(n+6)(n+8)(n+6)
=n=11(n+6)1(n+8)
Expand the summation.
n=11(n+6)1(n+8)=(17+18+19+110...)(19+110+...)
=17+18
=1556
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Jeffrey Jordon
Answered 2021-12-27 Author has 2313 answers

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