# (9.5×10^{11})+(6.3×10^{9}) Question
Algebra foundations $$\displaystyle{\left({9.5}×{10}^{{{11}}}\right)}+{\left({6.3}×{10}^{{{9}}}\right)}$$ 2021-03-10
To simplify this expression you just need to modify one of the terms so it has the same power of ten as the other. I find it easier to lower a power than raise it so we'll use the fact that $$\displaystyle{10}^{{{11}}}={100}×{10}^{{{9}}}.$$ Then
$$\displaystyle{9.5}×{\left({10}^{{{11}}}\right)}+{6.3}×{10}^{{{9}}}={9.5}×{100}×{\left({10}^{{{9}}}\right)}+{6.3}×{10}^{{{9}}}={950}×{\left({10}^{{{9}}}\right)}+{6.3}×{10}^{{{9}}}={\left({950}+{6.3}\right)}×{10}^{{{9}}}={956.3}×{10}^{{{9}}}$$
Note that if your course has recently covered maintaining significant figures, then you'll need to round this to the tens place. Hence your answer will instead be $$\displaystyle{950}×{10}^{{{9}}}={9.5}×{10}^{{{11}}}$$

### Relevant Questions A coffee manufacturer wants to market a new brand of coffee that sells for $4.10 per pound by mixing two coffees that sell for$2.75 and $5.00 per pound, respectively. What amounts of each coffee should be blended to obtain the desired mixture? asked 2021-01-30 A coffee manufacturer wants to market a new brand of coffee that sells for$4.10 per pound by mixing two coffees that sell for $2.75 and$5.00 per pound, respectively. What amounts of each coffee should be blended to obtain the desired mixture? Which of the systems of equations below could not be used to solve the following system for x and y? $$\displaystyle{6}{x}+{4}{y}={24}$$
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