Evaluate the integral int frac{1}{1+frac{x}{2}^2}dx

tabita57i

tabita57i

Answered question

2021-02-02

Evaluate the integral 11+x22dx

Answer & Explanation

pierretteA

pierretteA

Skilled2021-02-03Added 102 answers

The first step here will be a substitution to simplify that denominator.
u=1+x2
du=x2dx2du=dx
Substituting these in, we get
1u2×2du=2u2du
Now we just use the power rule for integrals.
=2[u11]+C=2u+c
And finally, we substitute back in for xx and simplify
=21+x2+C=42+x+c

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