Step 1

Consider the number of student tickets sold be x and the number of general admission tickets sold be y.

It is given that each student’s ticket cost is $4 and each general admission’s ticket cost is $6. The number of tickets sold is 525 and the amount collected is $2876.

According to the question, the equations are formed as

\(x+y=525\ and\ 4x+6y = 2876\)

Step 2

Solve the equations in order to find the values of x and y as follows.

\(4x+6(525-x)=2876 (\because y=525-x)\)

\(\displaystyle{4}{x}+{3150}-{6}{x}={2876}\)

\(\displaystyle-{2}{x}=-{274}\)

\(x=137\)

Step 3

Solve for y by substituting the value of x as follows.

\(137+y=525 (\because x=137)\)

\(y=525-137\)

\(y=388\)

Step 4

Check whether the values are correct or not.

\(4(137)+6(388)=2876\)

\(548+2328=2876\)

\(2876=2876\)(True)

Step 5

As the values for x and y satisfy the equations, the values of x and y are 137 and 388, respectively.

Therefore, the number of student tickets sold is 137 and the number of general admission tickets sold is 388.