You are selling tickets for a new college play: "A Handful of Math Miracles". Student tickets cost $4 and general admission tickets cost $6. You sell 525 tickets and collect $2876. How many of each type of ticket did you sell?

Step 1
Consider the number of student tickets sold be x and the number of general admission tickets sold be y.
It is given that each student’s ticket cost is $4 and each general admission’s ticket cost is $6. The number of tickets sold is 525 and the amount collected is $2876.
According to the question, the equations are formed as
$x+y=525and4x+6y=2876$

Step 2
Solve the equations in order to find the values of x and y as follows.
$4x+6(525-x)=2876(\because y=525-x)$
${\displaystyle 4x+3150-6x=2876}$
${\displaystyle -2x=-274}$
$x=137$
Step 3
Solve for y by substituting the value of x as follows.
$137+y=525(\because x=137)$
$y=525-137$
$y=388$
Step 4
Check whether the values are correct or not.
$4(137)+6(388)=2876$
$548+2328=2876$
$2876=2876$(True)
Step 5
As the values for x and y satisfy the equations, the values of x and y are 137 and 388, respectively.
Therefore, the number of student tickets sold is 137 and the number of general admission tickets sold is 388.