\(\displaystyle\frac{1}{{5}}{\left({2}{a}–{3}\right)}\)=

= \(\displaystyle\frac{1}{{5}}\cdot{2}{a}=\frac{1}{{5}}\cdot{3}\) =

= \(\displaystyle\frac{2}{{5}}{a}–\frac{3}{{5}}\)

Question

asked 2021-09-15

Simplify each rational expression. You will need to use factoring by grouping.

\(\displaystyle{\frac{{{x}^{{2}}-{2}{x}+{a}{x}-{2}{a}}}{{{x}^{{2}}-{2}{x}+{3}{a}{x}-{6}{a}}}}\)

\(\displaystyle{\frac{{{x}^{{2}}-{2}{x}+{a}{x}-{2}{a}}}{{{x}^{{2}}-{2}{x}+{3}{a}{x}-{6}{a}}}}\)

asked 2021-09-09

Find the indicated products. Assume all variables that appear as exponents represent positive integers.

\(\displaystyle{\left({x}^{{{2}{a}}}-{7}\right)}{\left({x}^{{{2}{a}}}-{3}\right)}\)

\(\displaystyle{\left({x}^{{{2}{a}}}-{7}\right)}{\left({x}^{{{2}{a}}}-{3}\right)}\)

asked 2021-09-09

Add or subtract the following polynomials.

\(\displaystyle{\left({2}{a}^{{3}}{b}+{1}\right)}+{\left({4}{a}^{{3}}{b}+{2}\right)}\)

\(\displaystyle{\left({2}{a}^{{3}}{b}+{1}\right)}+{\left({4}{a}^{{3}}{b}+{2}\right)}\)

asked 2021-09-09

Subtract the polynomials using the horizontal format. \(\displaystyle{2}{a}^{{2}}-{6}{a}-{4}\) from \(\displaystyle-{4}{a}^{{2}}+{6}{a}+{10}\)