Two spelunkers (cave explorers) were exploring different branches of an underground cavern. The first was able to descend 198 ft farther than twice the second. If the first spelunker descended a 1218 ft, how far was the second spelunker able to descend?

a2linetagadaW

a2linetagadaW

Answered question

2020-11-26

Two spelunkers (cave explorers) were exploring different branches of an underground cavern. The first was able to descend 198 ft farther than twice the second. If the first spelunker descended a 1218 ft, how far was the second spelunker able to descend?

Answer & Explanation

Nichole Watt

Nichole Watt

Skilled2020-11-27Added 100 answers

Let x be the distance the second spelunker descended so that the first spelunker descended 2x+198, both in ft.
2x+198=1218
2x=1020
x=510
The second spelunker was able to descend a distance of 510 feet.

Jeffrey Jordon

Jeffrey Jordon

Expert2021-08-11Added 2605 answers

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