# Two spelunkers (cave explorers) were exploring different branches of an underground cavern. The first was able to descend 198 ft farther than twice the second. If the first spelunker descended a 1218 ft, how far was the second spelunker able to descend?

Question
Two spelunkers (cave explorers) were exploring different branches of an underground cavern. The first was able to descend 198 ft farther than twice the second. If the first spelunker descended a 1218 ft, how far was the second spelunker able to descend?

2020-11-27
Let x be the distance the second spelunker descended so that the first spelunker descended 2x+198, both in ft.
Since the first spelunker descended a 1218 ft, we can write:
2x+198=1218
Subtract 198 from both sides:
2x=1020
Divide both sides by 2:
x=510
So, the second spelunker was able to descend a distance of 510 feet.

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