Given a triangles. One angle is 42^circ. Find the other angles if they're equal.

Question

Given a triangles. One angle is

42^{\circ}

. Find the other angles if they're equal.

Answer 1

Let each of the needed angles be x. Express in an equation.
$x + x + 42 = 180$
$2 x = 180 - 42$
$x = \frac{138}{2}$
$x = 69.$
Each of the remaining angles is $69^{\circ}$

Given a triangles. One angle is 42^circ. Find the other angles if they're equal.

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