# Given a triangles. One angle is 42^circ. Find the other angles if they're equal.

Given a triangles. One angle is ${42}^{\circ }$. Find the other angles if they're equal.
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firmablogF

Let each of the needed angles be x. Express in an equation.
$x+x+42=180$
$2x=180-42$
$x=\frac{138}{2}$
$x=69.$
Each of the remaining angles is ${69}^{\circ }$