Given a triangles. One angle is 42^circ. Find the other angles if they're equal.

Given a triangles. One angle is 42^circ. Find the other angles if they're equal.

Question
Given a triangles. One angle is \(\displaystyle{42}^{\circ}\). Find the other angles if they're equal.

Answers (1)

2021-02-01
Let each of the needed angles be x. Express in an equation.
x+x+42=180
2x=180-42
\(\displaystyle{x}=\frac{{138}}{{2}}\)
x=69.
Each of the remaining angles is 69^circ
0

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