Question

5 building's height's mu=56 m. Three of them are 58m, 55m and 53m. What is the mu for the 2 remaining buildings?

Data distributions
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asked 2021-02-25
5 building's height's \(\displaystyle\mu={56}\) m. Three of them are 58m, 55m and 53m. What is the mu for the 2 remaining buildings?

Answers (1)

2021-02-26
Let the sum of hight of the other 2 buildings be x. So their \(\displaystyle\mu=\frac{{x}}{{2}}.\)
\(\displaystyle\frac{{{58}+{55}+{53}+{x}}}{{5}}={56}\)
\(\displaystyle\frac{{{166}+{x}}}{{5}}={56}\)
\(\displaystyle{166}+{x}={280}\)
\(\displaystyle{x}={114}\)
Substitute to \(\displaystyle\mu=\frac{{x}}{{2}}.\)
\(\displaystyle\mu=\frac{{114}}{{2}}\)
\(\displaystyle\mu={57}\) m
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