Question

# 5 building's height's mu=56 m. Three of them are 58m, 55m and 53m. What is the mu for the 2 remaining buildings?

Data distributions
5 building's height's $$\displaystyle\mu={56}$$ m. Three of them are 58m, 55m and 53m. What is the mu for the 2 remaining buildings?

2021-02-26
Let the sum of hight of the other 2 buildings be x. So their $$\displaystyle\mu=\frac{{x}}{{2}}.$$
$$\displaystyle\frac{{{58}+{55}+{53}+{x}}}{{5}}={56}$$
$$\displaystyle\frac{{{166}+{x}}}{{5}}={56}$$
$$\displaystyle{166}+{x}={280}$$
$$\displaystyle{x}={114}$$
Substitute to $$\displaystyle\mu=\frac{{x}}{{2}}.$$
$$\displaystyle\mu=\frac{{114}}{{2}}$$
$$\displaystyle\mu={57}$$ m