Given System:

\(\displaystyle{5}{x}+{y}={8}---{\left({1}\right)}\)

\(\displaystyle{x}+{2}{y}={5}---{\left({2}\right)}\)

\(\text{Wecheck}(1, 3)\text{is a solution f system or}\neg\)

\(\text{No wat}(1,3)\)

\(\displaystyle{5}{x}+{y}={5}\cdot{1}+{3}={8}\)

\(\displaystyle{\quad\text{and}\quad}\)

\(\displaystyle{x}={2}{y}={1}+{2}\cdot{3}={1}+{6}={7}\ne{q}{5}\)

\(\text{There f or}\ e(1,3)\ \text{is}\ \neg\ \text{sati y}\ x+2y=5\)

\(\text{Hence}(1,3)\ \text{is}\ \neg\ \text{absolution f}\)

\(\displaystyle{5}{x}+{y}={8}\)

\(\displaystyle{x}+{2}{y}={5}\)