determine whether the statement is true or false. Justify your answer. 99. The equation 2 sin 4t − 1 = 0 has four times the number of solutions in the interval [0, 2pi) as the equation 2 sin t − 1 = 0.

Ava-May Nelson

Ava-May Nelson

Answered question

2021-01-10

determine whether the statement is true or false. Justify your answer.
99. The equation 2sin4t1=0 has four times the number of solutions in the interval [0,2π) as the equation 2sint1=0.

Answer & Explanation

funblogC

funblogC

Skilled2021-01-11Added 91 answers

We have:
2sin4t1=0(1)
2sint1=0(2)
From equation(1)
2sin4t1=0
sin4t=12
4t=sin1(12)
t=14(π6)
From equation(2)
2sint1=0
sint=22
t=sin1(12)
t=π6

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