Solving the following equations will require you to use the quadratic formula. Solve each equation for u between 0∘and360∘, and round your answers to the nearest tenth of a degree. cos⁡2u+sin⁡u=0

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Solving the following equations will require you to use the quadratic formula. Solve each equation for u between 0∘and360∘, and round your answers to the nearest tenth of a degree.  cos⁡2u+sin⁡u=0

Willie · Accepted Answer

We have, cos2u+sin⁡u=0 By using the identity, cos2u=1−sin⁡2u and solving further, cos2u+sin⁡u=0 1−sin2u+sin=0 sin2u−sin⁡u−1=0 The above equation is quadratic equation in variable sinu. Using the quadratic equation formula and solving it further, we get our result as sin⁡u=−(−1)±(−1)2−4(1)(−1)2(1) sin⁡u=1+52,1−52 Now, sin⁡u=1+52 No solution occurs because range for sine function lies between -1 to 1 For, sin⁡u=1−52 sin⁡u=0.618 u=sin−1(−0.618) u=−sin−1(0.618) u=38.17∘ u=360∘−38.17∘ u=321.82∘ Hence,value of u will be 321.82∘

Solving the following equations will require you to use the quadratic formula. Solve each equation for u between 0^(circ) and 360^(circ), and round your answers to the nearest tenth of a degree. cos2 u + sin u = 0

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