Let x be the cost of a ticket on Airline 1 and y be the cost of a ticket on Airline 2.

Two tickets from Airline 1 and three tickets from Airline 2 cost $900:

2x+3y=900(1)

One ticket from Airline 1 and four tickets from Airline 2 cost $950:

x+4y=950(2)

Solve by substitution. Solve for xx using (2) to obtain (3):

x=950−4y(3)

Substitute (3) to (1) and solve for yy:

2(950−4y)+3y=900

1900−8y+3y=900

−5y=−1000

y=200

Solve for x using (3):

x=950−4(200)

x=950−800

x=150

The cost of a ticket on Airline 1 is $150, and the cost of a ticket on Airline 2 is $200.

Two tickets from Airline 1 and three tickets from Airline 2 cost $900:

2x+3y=900(1)

One ticket from Airline 1 and four tickets from Airline 2 cost $950:

x+4y=950(2)

Solve by substitution. Solve for xx using (2) to obtain (3):

x=950−4y(3)

Substitute (3) to (1) and solve for yy:

2(950−4y)+3y=900

1900−8y+3y=900

−5y=−1000

y=200

Solve for x using (3):

x=950−4(200)

x=950−800

x=150

The cost of a ticket on Airline 1 is $150, and the cost of a ticket on Airline 2 is $200.