(a) In figure point A is in the fourth quadrant In the fourth quadrant X is positive and Y is negative .So the coordinate of A is (4,−3)
In figure point B is in the third quadrant .In the third quadrant X is negative and Y is also negative.So the coordinate of B is (−3,−1)

\(\displaystyle△{x}={x}{2}−{x}{1}\)

\(\displaystyle△{x}=−{3}−{4}=−{7}\)

\(\displaystyle△{y}={y}{2}−{y}{1}\)

\(\displaystyle△{y}=−{1}−{\left(−{3}\right)}=−{1}+{3}={2}\)

(b) In figure point A is in the first quadrant In the first quadrant X is positive and Y is also positive .So the coordinate of A is (2,1) In figure point B is in the second quadrant .In the second quadrant X is negative and Y is also positive .So the coordinate of B is (−4,3)

\(\displaystyle△{x}={x}{2}-{x}{1}\)

\(\displaystyle△{x}=−{4}−{2}=−{6}\)

\(\displaystyle△{y}={y}{2}−{y}{1}\)

\(\displaystyle△{y}={3}−{1}={2}\)

\(\displaystyle△{x}={x}{2}−{x}{1}\)

\(\displaystyle△{x}=−{3}−{4}=−{7}\)

\(\displaystyle△{y}={y}{2}−{y}{1}\)

\(\displaystyle△{y}=−{1}−{\left(−{3}\right)}=−{1}+{3}={2}\)

(b) In figure point A is in the first quadrant In the first quadrant X is positive and Y is also positive .So the coordinate of A is (2,1) In figure point B is in the second quadrant .In the second quadrant X is negative and Y is also positive .So the coordinate of B is (−4,3)

\(\displaystyle△{x}={x}{2}-{x}{1}\)

\(\displaystyle△{x}=−{4}−{2}=−{6}\)

\(\displaystyle△{y}={y}{2}−{y}{1}\)

\(\displaystyle△{y}={3}−{1}={2}\)