10

Question
Systems of equations
asked 2021-02-11
10−3=36
2+5=−4
solve using substitution

Answers (1)

2021-02-12
10x-3y = 36
10x = 36 + 3y
x = 3.6 + .3y
substitute x into second equation 2+5=−4
2(3.6 + .3y) + 5y = -4
7.2 + .6y + 5y = -4
7.2 + 5.6y = -4
5.6y = -11.2
y = -2
substitute y into either equation 2x + 5y = -4
2x + 5(-2) = -4
2x - 10 = -4
2x = 6
x = 3
answer: x = 3, y = -2
0

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