\(-2y+y=6\)

\(-y=6\)

\(y=-6\)

substitute y into second equation \(4x-2y=5\)

\(4x-2(-6)=5\)

\(4x+12=5\)

\(4x=-7\)

\(\displaystyle{x}=-\frac{{7}}{{4}}\)

answer: \(\displaystyle{x}=-\frac{{7}}{{4}}\),

\(y=-6\)

Question

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