Question

The square surface cover shown in the figure is 10.16 centimeters on each side. The knockout in the center of the cover has a diameter of 1.27 centimeters. Find the area of the cover to the nearest hundredth centimeter.

Circles
ANSWERED
asked 2020-11-08
The square surface cover shown in the figure is 10.16 centimeters on each side. The knockout in the center of the cover has a diameter of 1.27 centimeters. Find the area of the cover to the nearest hundredth centimeter.

Answers (1)

2020-11-09

The area of the cover is the area of the square minus the area of the circle: Acover=Asquare-Acircle Acover=\(\displaystyle{8}^{{2}}-\frac{{π{d}^{{2}}}}{{4}}\)
Substitute s=10.16 cm and d=1.27 cm: Acover=\(\displaystyle{10.16}^{{2}}-{\left(π\frac{{\left({1.27}\right)}^{{2}}}{{4}}\right)}\)
Use a calculator and round to the nearest hundredth cm (2 decimal places):
Acover≈101.96 cm

0
 
Best answer

expert advice

Have a similar question?
We can deal with it in 3 hours
...