Calculation:

Let the number of books be x .Since the printing and binding cost for a college algebra cost is \(\$10\) -The printing and binding cost for 10 algebra books is 10x The editorial cost is \(\$200, 000\). The first 2500 books are free.

Thus, the average cost of sealable books is

f(x) = total cost/number of sealable books

\(f(x)=\frac{10x+200,000}{x-2500}\)

Hence, the required function is \(f(x) = \frac{10x+200,000}{x-2500}\).

Let the number of books be x .Since the printing and binding cost for a college algebra cost is \(\$10\) -The printing and binding cost for 10 algebra books is 10x The editorial cost is \(\$200, 000\). The first 2500 books are free.

Thus, the average cost of sealable books is

f(x) = total cost/number of sealable books

\(f(x)=\frac{10x+200,000}{x-2500}\)

Hence, the required function is \(f(x) = \frac{10x+200,000}{x-2500}\).