By the Pythagorean Theorem, the sum of the squares of the legs aa and bb is equal to the square of the hypotenuse cc in a right triangle. Hence, we can write:

\(\displaystyle{7}^{{2}}+{8}^{{2}}={c}^{{2}}\)

\(\displaystyle{49}+{64}={c}^{{2}}\)

\(\displaystyle{113}={c}^{{2}}\)

\(\displaystyle{c}=√{113}≈{10.6}\)

\(\displaystyle{7}^{{2}}+{8}^{{2}}={c}^{{2}}\)

\(\displaystyle{49}+{64}={c}^{{2}}\)

\(\displaystyle{113}={c}^{{2}}\)

\(\displaystyle{c}=√{113}≈{10.6}\)