Question

BD bisects <ABC. Solve for x and find m<ABC.m<ABD=7x-5, m<CBD=4x+1x=?

Matrices
ANSWERED
asked 2021-02-11

BD bisects \(\displaystyle{<}{A}{B}{C}\). Solve for x and find m\(\displaystyle{m}{<}{A}{B}{D}={7}{x}-{5},{m}{<}{C}{B}{D}={4}{x}+{1}\) x=?

Expert Answers (2)

2021-02-12

Given:
\(\displaystyle{m}∠{A}{B}{D}={7}{x}−{5}\)
\(m∠CBD=4x+1\)
BD bisects \(\displaystyle∠{A}{B}{C}\)
x=?
When BD bisects \(\displaystyle∠{A}{B}{C}\) then \(\displaystyle∠{A}{B}{D}=∠{D}{B}{C}\)
7x−5=4x+1
Subtract 4x both the sides:
7x−5−4x=4x+1
3x−5=1
Add 5 both the sides:
3x−5+5=1+5
3x=6
Divide 3 by both the sides:
3x3=63
x=2
Hence value of x ix 2

20
 
Best answer
2021-08-10

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