BD bisects

BD bisects <ABC. Solve for x and find m<ABC. m<ABD=7x-5, m<CBD=4x+1 x=?

Question
BD bisects \(\displaystyle{<}{A}{B}{C}\)</span>. Solve for x and find m\(\displaystyle{m}{<}{A}{B}{D}={7}{x}-{5},{m}{<}{C}{B}{D}={4}{x}+{1}\)</span> x=?

Answers (1)

2021-02-12
Given:
\(\displaystyle{m}∠{A}{B}{D}={7}{x}−{5}\)
m∠CBD=4x+1ZSK
BD bisects \(\displaystyle∠{A}{B}{C}\)
x=?
When BD bisects \(\displaystyle∠{A}{B}{C}\) then \(\displaystyle∠{A}{B}{D}=∠{D}{B}{C}\)
7x−5=4x+1
Subtract 4x both the sides:
7x−5−4x=4x+1
3x−5=1
Add 5 both the sides:
3x−5+5=1+5
3x=6
Divide 3 by both the sides:
3x3=63
x=2
Hence value of x ix 2
0

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