Given:

Number of freshmen = 14

Number of sophomores = 21

Number of juniors = 9

Number of seniors = 1

Formula Used:

Let E denote the event of the Professor selecting the senior to answer a question and S denote the sample space. Then, P(E) denotes the probability that E occurs. The probability is given by,

\(P(E)=\frac{n(E)}{n(S)}\)

Where, n(E) denotes the number of elements in E and n(S) denotes the number of elements in S.

Calculation:

Calculate the total number of students enrolled in the college algebra class.

Total number of students enrolled in the college algebra class = 14+21+9+1=45

The probability that the Professor randomly selects the senior to answer a question is given by,

\(P(E)=\frac{n(E)}{n(S)}\)

=Number of seniors in class/Total number of students in class

\(=\frac{1}{45}\approx 0.0222\)

Number of freshmen = 14

Number of sophomores = 21

Number of juniors = 9

Number of seniors = 1

Formula Used:

Let E denote the event of the Professor selecting the senior to answer a question and S denote the sample space. Then, P(E) denotes the probability that E occurs. The probability is given by,

\(P(E)=\frac{n(E)}{n(S)}\)

Where, n(E) denotes the number of elements in E and n(S) denotes the number of elements in S.

Calculation:

Calculate the total number of students enrolled in the college algebra class.

Total number of students enrolled in the college algebra class = 14+21+9+1=45

The probability that the Professor randomly selects the senior to answer a question is given by,

\(P(E)=\frac{n(E)}{n(S)}\)

=Number of seniors in class/Total number of students in class

\(=\frac{1}{45}\approx 0.0222\)