To find:The classical probability.

kuCAu
2020-12-02
Answered

To find:The classical probability.

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comentezq

Answered 2020-12-03
Author has **106** answers

Given:

Number of freshmen = 14

Number of sophomores = 21

Number of juniors = 9

Number of seniors = 1

Formula Used:

Let E denote the event of the Professor selecting the senior to answer a question and S denote the sample space. Then, P(E) denotes the probability that E occurs. The probability is given by,

$P(E)=\frac{n(E)}{n(S)}$

Where, n(E) denotes the number of elements in E and n(S) denotes the number of elements in S.

Calculation:

Calculate the total number of students enrolled in the college algebra class.

Total number of students enrolled in the college algebra class = 14+21+9+1=45

The probability that the Professor randomly selects the senior to answer a question is given by,

$P(E)=\frac{n(E)}{n(S)}$

=Number of seniors in class/Total number of students in class

$=\frac{1}{45}\approx 0.0222$

Number of freshmen = 14

Number of sophomores = 21

Number of juniors = 9

Number of seniors = 1

Formula Used:

Let E denote the event of the Professor selecting the senior to answer a question and S denote the sample space. Then, P(E) denotes the probability that E occurs. The probability is given by,

Where, n(E) denotes the number of elements in E and n(S) denotes the number of elements in S.

Calculation:

Calculate the total number of students enrolled in the college algebra class.

Total number of students enrolled in the college algebra class = 14+21+9+1=45

The probability that the Professor randomly selects the senior to answer a question is given by,

=Number of seniors in class/Total number of students in class

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Please explain at beginner level.

${\int}_{0}^{1}\sqrt{{x}^{2}-2x+1}dx$

so I simplified it algebraically to

${\int}_{0}^{1}\sqrt{(x-1{)}^{2}}dx$

which of course is

${\int}_{0}^{1}|x-1|dx$

as the absolute value is a linear function over $x\in [0,\mathrm{\infty})$ so I proceed to evaluate it as ${x}^{2}/2-x$ for upper limit 1 and lower limit 0 which is $((1{)}^{2}/2-1)-(0-0)$ and equals $-\frac{1}{2}$, but according to wolfram alpha it is $\frac{1}{2}$.

Please explain at beginner level.

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Given Information:

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Given Information:

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