To find the lowest original score that will result in an A if the professor uses (i)(f*g)(x) and (ii)(g*f)(x). Professor Harsh gave a test to his college algebra class and nobody got more than 80 points (out of 100) on the test. One problem worth 8 points had insufficient data, so nobody could solve that problem. The professor adjusted the grades for the class by a. Increasing everyone's score by 10% and b. Giving everyone 8 bonus points c. x represents the original score of a student

Question
Upper level algebra
asked 2021-03-05
To find the lowest original score that will result in an A if the professor uses
\((i)(f*g)(x)\ and\ (ii)(g*f)(x)\).
Professor Harsh gave a test to his college algebra class and nobody got more than 80 points (out of 100) on the test.
One problem worth 8 points had insufficient data, so nobody could solve that problem.
The professor adjusted the grades for the class by
a. Increasing everyone's score by 10% and
b. Giving everyone 8 bonus points
c. x represents the original score of a student

Answers (1)

2021-03-06
The function \(f(x) = 1.1\) xrepresents the score increased by 10%
The function \(g(x) = x + 8\) represents the score increased by 8 points
The function \((f*g)(x) = 1.1(x + 8)\) represents the final score when the score is first increased by 8 bonus points and then by 10%
The function \((g*f)(x) = l.lx + 8\) represents the final score when the score is first increased by 10% and then by 8 bonus points
A score of 90 or better results in an A
Calculation:
(i) Consider \((f*g)(x) = 1.1 (x+8)\)
Plugging the final score of 90,
\(90 = 1.1 (x+8)\)
Dividing by 1.1 on both the sides,
\(\frac{90}{1.1}=\frac{1.1(x+8)}{1.1}\)
\(81.8181... =x+8\)
\(x+8=818181...\)
\(x+8= 81.82\)
Subtracting 8 from both the sides,
\(x+8-8=81.82-8\)
\(x= 73.82\)
(ii) Consider \((g*f)(x) = 1.1x +8\)
Plugging the final score of 90,
\(90 = 1.1x+8\)
Subtracting 8 from both the sides,
\(90-8 = 1.1x+8-8\)
\(82= 1.1x\)
\(1.1x = 82\)
Dividing by 1.1 on both the sides,
\(\frac{1.1x}{1.1}=\frac{82}{1.1}\)
\(x= 74.5454...\)
\(x= 74.55\).
0

Relevant Questions

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To calculate:To check if(f*g)(x)=(g*f)(x). Professor Harsh gave a test to his college algebra class and nobody got more than 80 points (out of 100) on the test. One problem worth 8 points had insufficient data, so nobody could solve that problem.
The professor adjusted the grades for the class by
a. Increasing everyone's score by 10% and
b. Giving everyone 8 bonus points
c. x represents the original score of a student
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To calculate:To evaluate \((f*g)(70)\ and\ (g*f)(70)\).
Professor Harsh gave a test to his college algebra class and nobody got more than 80 points (out of 100) on the test.
One problem worth 8 points had insufficient data, so nobody could solve that problem.
The professor adjusted the grades for the class by
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To calculate: To write the given statements (a) and (b) as functions f(x) and g(x)respectively.
Professor Harsh gave a test to his college algebra class and nobody got more than 80 points (out of 100) on the test.
One problem worth 8 points had insufficient data, so nobody could solve that problem.
The professor adjusted the grades for the class by
a. Increasing everyone's score by 10% and
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The table below shows the number of people for three different race groups who were shot by police that were either armed or unarmed. These values are very close to the exact numbers. They have been changed slightly for each student to get a unique problem.
Suspect was Armed:
Black - 543
White - 1176
Hispanic - 378
Total - 2097
Suspect was unarmed:
Black - 60
White - 67
Hispanic - 38
Total - 165
Total:
Black - 603
White - 1243
Hispanic - 416
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Give your answer as a decimal to at least three decimal places.
a) What percent are Black?
b) What percent are Unarmed?
c) In order for two variables to be Independent of each other, the P \((A and B) = P(A) \cdot P(B) P(A and B) = P(A) \cdot P(B).\)
This just means that the percentage of times that both things happen equals the individual percentages multiplied together (Only if they are Independent of each other).
Therefore, if a person's race is independent of whether they were killed being unarmed then the percentage of black people that are killed while being unarmed should equal the percentage of blacks times the percentage of Unarmed. Let's check this. Multiply your answer to part a (percentage of blacks) by your answer to part b (percentage of unarmed).
Remember, the previous answer is only correct if the variables are Independent.
d) Now let's get the real percent that are Black and Unarmed by using the table?
If answer c is "significantly different" than answer d, then that means that there could be a different percentage of unarmed people being shot based on race. We will check this out later in the course.
Let's compare the percentage of unarmed shot for each race.
e) What percent are White and Unarmed?
f) What percent are Hispanic and Unarmed?
If you compare answers d, e and f it shows the highest percentage of unarmed people being shot is most likely white.
Why is that?
This is because there are more white people in the United States than any other race and therefore there are likely to be more white people in the table. Since there are more white people in the table, there most likely would be more white and unarmed people shot by police than any other race. This pulls the percentage of white and unarmed up. In addition, there most likely would be more white and armed shot by police. All the percentages for white people would be higher, because there are more white people. For example, the table contains very few Hispanic people, and the percentage of people in the table that were Hispanic and unarmed is the lowest percentage.
Think of it this way. If you went to a college that was 90% female and 10% male, then females would most likely have the highest percentage of A grades. They would also most likely have the highest percentage of B, C, D and F grades
The correct way to compare is "conditional probability". Conditional probability is getting the probability of something happening, given we are dealing with just the people in a particular group.
g) What percent of blacks shot and killed by police were unarmed?
h) What percent of whites shot and killed by police were unarmed?
i) What percent of Hispanics shot and killed by police were unarmed?
You can see by the answers to part g and h, that the percentage of blacks that were unarmed and killed by police is approximately twice that of whites that were unarmed and killed by police.
j) Why do you believe this is happening?
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