Simplify add the numbers to obtain:

1=1

1+2=3

1+2+3=

1+2+3+4=10

1+2+3+4+5=15

1=1

1+2=3

1+2+3=

1+2+3+4=10

1+2+3+4+5=15

Question

asked 2020-12-24

a student is speeding down route 11 in his fancy red Porschewhen his radar system warns him of an obstacle 400 ft ahead. heimmediately applies the brakes, starts to slow down and spots askunk in the road directly ahead of him. the "black box" in thePorsche records the car's speed every 2 seconds , producing thefollowing table. the speed decreases throughout the 10 seconds ittakes to stop, although not necessarily at a uniform rate.

time since brakes applied (sec) 0 2 4 6 8 10

speed(ft/sec) 100 80 50 25 10 0

a) what is your best estimate of the total distance thestudent's car travelled before coming to rest?

b) which one of the following statements can you justify fromthe information given?

1) the car stopped before getting to the skunk.

2) the " black box" data is inconclusive. the skunk may or maynot have been hit.

3) the skunk was hit by the car.

time since brakes applied (sec) 0 2 4 6 8 10

speed(ft/sec) 100 80 50 25 10 0

a) what is your best estimate of the total distance thestudent's car travelled before coming to rest?

b) which one of the following statements can you justify fromthe information given?

1) the car stopped before getting to the skunk.

2) the " black box" data is inconclusive. the skunk may or maynot have been hit.

3) the skunk was hit by the car.

asked 2021-02-12

The approximate metric measurement of length is given for a U.S. customary unit of length. Use your estimation skills to complete the graphic organizer below. Fill in each blank with foot, yard, inch, or mile.
Metric Customary 2.54 centimeters→1 0.30 meter→1 0.91 meter→1 1.61 kilometers→1

asked 2021-02-23

Interpreting z-scores: Complete the following statements using your knowledge about z-scores.

a. If the data is weight, the z-score for someone who is overweight would be

-positive

-negative

-zero

b. If the data is IQ test scores, an individual with a negative z-score would have a

-high IQ

-low IQ

-average IQ

c. If the data is time spent watching TV, an individual with a z-score of zero would

-watch very little TV

-watch a lot of TV

-watch the average amount of TV

d. If the data is annual salary in the U.S and the population is all legally employed people in the U.S., the z-scores of people who make minimum wage would be

-positive

-negative

-zero

a. If the data is weight, the z-score for someone who is overweight would be

-positive

-negative

-zero

b. If the data is IQ test scores, an individual with a negative z-score would have a

-high IQ

-low IQ

-average IQ

c. If the data is time spent watching TV, an individual with a z-score of zero would

-watch very little TV

-watch a lot of TV

-watch the average amount of TV

d. If the data is annual salary in the U.S and the population is all legally employed people in the U.S., the z-scores of people who make minimum wage would be

-positive

-negative

-zero

asked 2020-12-29

Let A={1, 2, 3, 4, 5, 6, 7, 8, 9}

a) If five integers are selected from A, must at least one pair of the integer have a sume of 9?

a) If five integers are selected from A, must at least one pair of the integer have a sume of 9?

asked 2021-01-17

A new thermostat has been engineered for the frozen food cases in large supermarkets. Both the old and new thermostats hold temperatures at an average of \(25^{\circ}F\). However, it is hoped that the new thermostat might be more dependable in the sense that it will hold temperatures closer to \(25^{\circ}F\). One frozen food case was equipped with the new thermostat, and a random sample of 21 temperature readings gave a sample variance of 5.1. Another similar frozen food case was equipped with the old thermostat, and a random sample of 19 temperature readings gave a sample variance of 12.8. Test the claim that the population variance of the old thermostat temperature readings is larger than that for the new thermostat. Use a \(5\%\) level of significance. How could your test conclusion relate to the question regarding the dependability of the temperature readings? (Let population 1 refer to data from the old thermostat.)

(a) What is the level of significance?

State the null and alternate hypotheses.

\(H0:?_{1}^{2}=?_{2}^{2},H1:?_{1}^{2}>?_{2}^{2}H0:?_{1}^{2}=?_{2}^{2},H1:?_{1}^{2}\neq?_{2}^{2}H0:?_{1}^{2}=?_{2}^{2},H1:?_{1}^{2}?_{2}^{2},H1:?_{1}^{2}=?_{2}^{2}\)

(b) Find the value of the sample F statistic. (Round your answer to two decimal places.)

What are the degrees of freedom?

\(df_{N} = ?\)

\(df_{D} = ?\)

What assumptions are you making about the original distribution?

The populations follow independent normal distributions. We have random samples from each population.The populations follow dependent normal distributions. We have random samples from each population.The populations follow independent normal distributions.The populations follow independent chi-square distributions. We have random samples from each population.

(c) Find or estimate the P-value of the sample test statistic. (Round your answer to four decimal places.)

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?

At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant. At the ? = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant.At the ? = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant.

(e) Interpret your conclusion in the context of the application.

Reject the null hypothesis, there is sufficient evidence that the population variance is larger in the old thermostat temperature readings.Fail to reject the null hypothesis, there is sufficient evidence that the population variance is larger in the old thermostat temperature readings. Fail to reject the null hypothesis, there is insufficient evidence that the population variance is larger in the old thermostat temperature readings.Reject the null hypothesis, there is insufficient evidence that the population variance is larger in the old thermostat temperature readings.

(a) What is the level of significance?

State the null and alternate hypotheses.

\(H0:?_{1}^{2}=?_{2}^{2},H1:?_{1}^{2}>?_{2}^{2}H0:?_{1}^{2}=?_{2}^{2},H1:?_{1}^{2}\neq?_{2}^{2}H0:?_{1}^{2}=?_{2}^{2},H1:?_{1}^{2}?_{2}^{2},H1:?_{1}^{2}=?_{2}^{2}\)

(b) Find the value of the sample F statistic. (Round your answer to two decimal places.)

What are the degrees of freedom?

\(df_{N} = ?\)

\(df_{D} = ?\)

What assumptions are you making about the original distribution?

The populations follow independent normal distributions. We have random samples from each population.The populations follow dependent normal distributions. We have random samples from each population.The populations follow independent normal distributions.The populations follow independent chi-square distributions. We have random samples from each population.

(c) Find or estimate the P-value of the sample test statistic. (Round your answer to four decimal places.)

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?

At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.At the ? = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant. At the ? = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant.At the ? = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant.

(e) Interpret your conclusion in the context of the application.

Reject the null hypothesis, there is sufficient evidence that the population variance is larger in the old thermostat temperature readings.Fail to reject the null hypothesis, there is sufficient evidence that the population variance is larger in the old thermostat temperature readings. Fail to reject the null hypothesis, there is insufficient evidence that the population variance is larger in the old thermostat temperature readings.Reject the null hypothesis, there is insufficient evidence that the population variance is larger in the old thermostat temperature readings.

asked 2021-01-28

A linear regression was performed on a bivariate data set with variables x and y. Analysis by a computer software package included the following outputs:

Sample Size: \(n=15\)

Regression Equation: \(y\hat{e} =0.359 - 1.264x\)

Coefficient of Determination: r square = 0.915

Sums of Squares :\(SSy = 35.617. SSex = 32.589, SSresid = 3.028\)

a. Calculate the standard error Se.

b. write a sentence interpreting the value of rsquare.

c.What is the value of Pearson's correlation coefficient?

d. Determine whether the variables x and y are significant using a \(5\%\) significance level. You may assume a simple random sample from a bivariate normal populaton.

Sample Size: \(n=15\)

Regression Equation: \(y\hat{e} =0.359 - 1.264x\)

Coefficient of Determination: r square = 0.915

Sums of Squares :\(SSy = 35.617. SSex = 32.589, SSresid = 3.028\)

a. Calculate the standard error Se.

b. write a sentence interpreting the value of rsquare.

c.What is the value of Pearson's correlation coefficient?

d. Determine whether the variables x and y are significant using a \(5\%\) significance level. You may assume a simple random sample from a bivariate normal populaton.

asked 2021-02-12

Michelle is studying the relationship between the hours worked (per week) and time spent reading (per day) and has collected the data shown in the table. The line of best fit for the data is \(y=−0.79x+98.8\).

Hours Worked (per week) 30405060 Minutes Reading (per day) 75685852

(a) According to the line of best fit, the predicted number of minutes spent reading for a person who works 27 hours (per week) is 77.47.

(b) Is it reasonable to use this line of best fit to make the above prediction?

Select the correct answer below:

1.The estimate, a predicted time of 77.47 minutes, is unreliable but reasonable.

2.The estimate, a predicted time of 77.47 minutes, is reliable but unreasonable.

3.The estimate, a predicted time of 77.47 minutes, is both unreliable and unreasonable.

4.The estimate, a predicted time of 77.47 minutes, is both reliable and reasonable.

Hours Worked (per week) 30405060 Minutes Reading (per day) 75685852

(a) According to the line of best fit, the predicted number of minutes spent reading for a person who works 27 hours (per week) is 77.47.

(b) Is it reasonable to use this line of best fit to make the above prediction?

Select the correct answer below:

1.The estimate, a predicted time of 77.47 minutes, is unreliable but reasonable.

2.The estimate, a predicted time of 77.47 minutes, is reliable but unreasonable.

3.The estimate, a predicted time of 77.47 minutes, is both unreliable and unreasonable.

4.The estimate, a predicted time of 77.47 minutes, is both reliable and reasonable.

asked 2021-01-02

Evaluate the expression \(\displaystyle\frac{\sqrt{{-{6}}}}{{\sqrt{{-{3}}}\sqrt{{-{4}}}}}\) and write the result in the form a+bi

asked 2021-05-25

Which of the following is the correct complete factorization of \(x^{4} - 1\)?

asked 2020-11-08

Replacement of paint on highways and streets represents a large investment of funds by state and local governments each year. A new, cheaper brand of paint is tested for durability after one month’s time by reflectometer readings. For the new brand to be acceptable, it must have a mean reflectometer reading greater than 19.6. The sample data, based on 35 randomly selected readings, show \(x =19.8\ and\ s=1.5\). Do the sample data provide sufficient evidence to conclude that the new brand is acceptable? Conduct hypothesis test using \(a=.05\). Use the traditional approach and the p-value approach to hypothesis testing! Show all of the steps of the hypothesis test for each approach.