a.Any of the three letters can be an outcome in each spin so the sample space is:

AA,AB,AC,BA,BB,BC,CA,CB,CC

b.Check for outcomes that have one or two A’s. There are 5 outcomes that have one or two A’s out of the sample space of 9. So, the probability is:

\(\displaystyle\frac{{5}}{{9}}\)

AA,AB,AC,BA,BB,BC,CA,CB,CC

b.Check for outcomes that have one or two A’s. There are 5 outcomes that have one or two A’s out of the sample space of 9. So, the probability is:

\(\displaystyle\frac{{5}}{{9}}\)