Let:

y=2x−3(1)

5x+y=11(2)

Solve by substitution. Substitute (1) to (2) and solve for x:

5x+(2x−3)=11

7x−3=11

7x=14

x=2

Solve for yy using (1):

y=2(2)−3

y=1

So, the solution of the system is:

(2,1)

which is choice A.

y=2x−3(1)

5x+y=11(2)

Solve by substitution. Substitute (1) to (2) and solve for x:

5x+(2x−3)=11

7x−3=11

7x=14

x=2

Solve for yy using (1):

y=2(2)−3

y=1

So, the solution of the system is:

(2,1)

which is choice A.